Hi New to the forum and looking for some help on something that is really driving me mad I am putting on LED indicators to replace some old aftermarket lights. The LEDs are about 1W instead of the 21W bulbs so I had planned to add in 2x 18W resistors on each side. I put it all together but the flash rate is way too high and I needed to add in 4x 18W resistors on one side to get it down to about 100 per min. I'm pretty sure they really are 18W resistors - from Oxford. Any ideas? Could it be a faulty relay? Is putting on 4 resistors each side a problem? I worried about the heat generated and the current draw. Would be great if anyone could help! Thanks CBR100RR5 (2005)
Hi, I put leds on the front with a 10w resistor, it is not only the wattage that is important it is the resistance.I shall try to find what ohm I fitted
+1 on the relay. load resisters are junk they get way to hot and will not last long! go with the relay
The relay's are fairly cheap as well. I paid $12 for mine from TST and it has an adjuster on it so you can change the flash rate.
Thanks everyone Will get a new relay and hope the pins fit...... Jez, thanks, your answer made me dig some more. Turns out the wattage rating is the maximum for the resistor, not the power at 12v. Each 21 W bulb will draw about 2 A. So it needs about 35 ohms resistance added each side which explains why I had to put 4 of the resistors on. Too much... I'll put my sons textbook away now and get on ebay Thanks
I put 2 10w leds in each front indicator, The idea being less reflection for speed guns, the headlight has also gone, I only ride in daylight. from memory the std flasher unit works from about 15w a bulb, so I ran leds to 5w and resistor 10w, the rears are std, I totally agree easiest way is new flasher relay but I am from yorkshire and cheapist I could find at the time was about £40 or 2 resistors £1.60
